Question:medium

When two light waves of equal intensity superimpose, the maximum intensity obtained is I. If the intensity of one of the waves is quadrupled, then the maximum intensity obtained is

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Remember that intensity is proportional to the square of the amplitude (\(I \propto A^2\)). Therefore, the maximum intensity formula \(I_{max} = (\sqrt{I_1} + \sqrt{I_2})^2\) is equivalent to adding the amplitudes for constructive interference: \(A_{max} = A_1 + A_2\), and then squaring.

Updated On: Mar 30, 2026

\( \frac{4I}{9} \)
\( \frac{9I}{4} \)
\( \frac{2I}{3} \)
\( \frac{3I}{2} \)

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The Correct Option is B

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