Question:medium

When a photosensitive material is illuminated by photons of energy 3.1 eV, the stopping potential of the photoelectrons is 1.7 V. When the same photosensitive material is illuminated by photons of energy 2.5 eV, the stopping potential of the photoelectrons is

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If energies are given in eV and stopping potential in V, you can treat them as numerically equal in the equation $E = \phi + V_s$.

Updated On: Mar 26, 2026

1.8 V
1.4 V
1.1 V
1.3 V

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The Correct Option is C

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