




To determine the major product of the given reaction, we must analyze the reaction conditions and mechanism involved. The reaction involves an aldehyde in the presence of a base (OH−) and water (H2O). This setup is a classic example of an aldol condensation reaction.
An aldol condensation involves two main steps:
Now, let's consider the reaction given:
The substrate is an aldehyde with an available alpha-hydrogen. The process leads to the formation of the major aldol condensation product through these steps:
The final product after the aldol condensation is the α,β-unsaturated aldehyde. Thus, the correct major product is:
Conclusion: The major product of the reaction is the α,β-unsaturated aldehyde formed via aldol condensation.
1 gram of sodium hydroxide was treated with 25 ml. of 0.75 M HCI solution, the mass of sodium hydroxide left unreacted is equal to :
List-I | List-II | ||
| (A) | NH3 | (I) | Trigonal Pyramidal |
| (B) | BrF5 | (II) | Square Planar |
| (C) | XeF4 | (III) | Octahedral |
| (D) | SF6 | (IV) | Square Pyramidal |