Question:medium

Match List I with List II

List-I
(Compound)

List-II
(Shape/geometry)

(A)NH3(I)Trigonal Pyramidal
(B)BrF5(II)Square Planar
(C)XeF4(III)Octahedral
(D)SF6(IV)Square Pyramidal

Choose the correct answer from the options given below:

Updated On: Jan 13, 2026
  • A-I, B-IV, C-II, D-III
  • A-II, B-IV, C-III, D-I
  • A-III, B-IV, C-I, D-II
  • A-II, B-III, C-IV, D-I
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Analyze Compound Geometries

  • A. \( NH_3 \) (Ammonia):
    • Structure: Trigonal pyramidal.
    • Central atom: Nitrogen, bonded to three hydrogen atoms and possessing one lone pair.
  • B. \( BrF_5 \) (Bromine Pentafluoride):
    • Geometry: Square pyramidal.
    • Central atom: Bromine, bonded to five fluorine atoms and possessing one lone pair.
  • C. \( XeF_4 \) (Xenon Tetrafluoride):
    • Geometry: Square planar.
    • Central atom: Xenon, bonded to four fluorine atoms and possessing two lone pairs.
  • D. \( SF_6 \) (Sulfur Hexafluoride):
    • Geometry: Octahedral.
    • Central atom: Sulfur, surrounded by six fluorine atoms.

Step 2: Match Compounds to Geometries

  • A-I: \( NH_3 \) corresponds to trigonal pyramidal geometry.
  • B-IV: \( BrF_5 \) corresponds to square pyramidal geometry.
  • C-II: \( XeF_4 \) corresponds to square planar geometry.
  • D-III: \( SF_6 \) corresponds to octahedral geometry.

Step 3: Conclusion

The established matches are:

A-I, B-IV, C-II, D-III

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