Water is flowing steadily with certain initial velocity vertically down from a tap of area of cross-section $1.8\text{ cm}^2$. At a distance 25 cm below the tap, area of cross-section of the stream of the water is $1.2\text{ cm}^2$. The mass of the water flowing from the tap in a time of 10 s is (Acceleration due to gravity $=10\text{ ms}^{-2}$)}
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For liquid streams:
\[
A_1v_1=A_2v_2
\]
and use Bernoulli's principle or kinematics to relate velocities.