A rain drop of diameter 1 mm falls with a terminal velocity of 0.7 ms$^{-1}$ in air. If the coefficient of viscosity of air is $2\times10^{-5}$ Pas, the viscous force on the rain drop is
Show Hint
Stokes' Law, $F_v = 6\pi\eta r v$, describes the drag force on a sphere moving slowly through a viscous fluid. Remember that at terminal velocity, this viscous drag force exactly balances the net downward force (gravity minus buoyancy).