Question:medium

The maximum length of water column that can stay without falling in a vertically held capillary tube of diameter 1mm and open at both the ends is (Acceleration due to gravity = 10 ms$^{-2}$ and surface tension of water = 0.07 Nm$^{-1}$)

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The height of capillary rise (or depression) is given by Jurin's Law: $h = \frac{2T\cos\theta}{r\rho g}$. For clean water in a glass tube, the contact angle $\theta$ is close to 0, so $\cos\theta \approx 1$. Be aware that exam questions can sometimes contain typos in the given data.
Updated On: Mar 30, 2026
  • 2.8 cm
  • 5.6 cm
  • 1.4 cm
  • 0 cm
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The Correct Option is B

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