Question:medium
Two rings of equal radius \(R\) arranged perpendicular to each other with common center at \(C\), carrying equal current \(I\). Find magnetic field at \(C\).
Two rings of equal radius \(R\) arranged perpendicular to each other with common center at \(C\), carrying equal current \(I\). Find magnetic field at \(C\).
Updated On: Mar 25, 2026
- \(\frac{μ_0I}{2R}\)
- \(\frac{μ_0I}{R}\)
- \(\sqrt{\frac{2μ_0I}{R}}\)
- \(\frac{μ_0I}{\sqrt{2R}}\)
Show Solution
The Correct Option is A
Solution and Explanation
Option (D) is: \( \frac{μ_0I}{\sqrt{2R}} \)
Was this answer helpful?
1
Top Questions on Magnetic Field
- Four long straight thin wires are held vertically at the corners A, B, C and D of a square of side \( a \), kept on a table and carry equal current \( I \). The wire at A carries current in upward direction whereas the current in the remaining wires flows in downward direction. The net magnetic field at the centre of the square will have the magnitude:
- CBSE Class XII - 2026
- Physics
- Magnetic Field
- A charged particle with charge \( q \) and velocity \( \vec{v} \) moves perpendicular to a magnetic field \( \vec{B} \). The radius of the circular path is \( r \). What is the expression for \( r \)?
- CUET (UG) - 2025
- Physics
- Magnetic Field
- Considering the case of magnetic field produced by air-filled current carrying solenoid, show that the magnetic energy density of a magnetic field \( B \) is \( \frac{B^2}{2\mu_0} \).
- CBSE Class XII - 2025
- Physics
- Magnetic Field
- A solid sphere is rolling without slipping on a horizontal plane. The ratio of the linear kinetic energy of the centre of mass of the sphere and rotational kinetic energy is:
- JEE Main - 2025
- Physics
- Magnetic Field
- Want to practice more? Try solving extra ecology questions todayView All Questions
