Two radioactive substances A and B have same number of initial nuclei. If the half-lives of A and B are 1.5 days and 4.5 days respectively, then the ratio of the number of nuclei remaining in A and B after 9 days is
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Ratio of remaining nuclei $N_A/N_B = (1/2)^{n_A - n_B}$. Here $n_A - n_B = 6 - 2 = 4$. Ratio is $(1/2)^4 = 1/16$.