Question:medium

Two radioactive substances A and B have same number of initial nuclei. If the half-lives of A and B are 1.5 days and 4.5 days respectively, then the ratio of the number of nuclei remaining in A and B after 9 days is

Show Hint

Ratio of remaining nuclei $N_A/N_B = (1/2)^{n_A - n_B}$. Here $n_A - n_B = 6 - 2 = 4$. Ratio is $(1/2)^4 = 1/16$.
Updated On: Mar 26, 2026
  • 1:16
  • 1:1
  • 1:4
  • 1:8
Show Solution

The Correct Option is A

Solution and Explanation

Was this answer helpful?
0