Step 1: Basic Principle
For two identical cells (emf \(E\), internal resistance \(r\)), current in series: \(I_s = \dfrac{2E}{2r+R}\); current in parallel: \(I_p = \dfrac{E}{r/2 + R}\).
Step 2: Solution Procedure:
Setting \(I_s = I_p\):
\[
\frac{2E}{2r + R} = \frac{E}{r/2 + R}
\]
\[
2(r/2 + R) = 2r + R
\]
\[
r + 2R = 2r + R
\]
\[
R = r
\]
So \(r = R = 1.5\ \Omega\).
Step 3: Required Answer:
The internal resistance of each cell is 1.5 \(\Omega\).