Question:medium

In a single slit diffraction pattern, the distance between the first minimum on the left and the first minimum on the right is $5\mathrm{mm}$. The screen on which the diffraction pattern is displayed is at a distance of $80~\mathrm{cm}$ from the slit. The wavelength is $6000\mathrm{\AA}$. The slit width in (mm) is about

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Slit width for single-slit diffraction: $w = \frac{D\lambda}{y_1}$, where $y_1$ is the distance from the centre to the first minimum.
Updated On: Apr 8, 2026
  • $0.576$
  • $0.348$
  • $0.192$
  • $0.096$
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The Correct Option is C

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