To solve the problem of finding the common potential when two capacitors are connected in parallel with opposite polarity, we will follow these steps:
- Calculate the initial charge on both capacitors:
- The charge on the first capacitor, \( C_1 = C \), charged to a potential \( V \), is given by: \(Q_1 = C \times V\)
- The charge on the second capacitor, \( C_2 = 2C \), charged to a potential \( 2V \), is given by: \(Q_2 = 2C \times 2V = 4CV\)
- Determine the net charge when connected with opposite polarity:
- Because they are connected with opposite polarity, the charges subtract: \(Q_{\text{net}} = -(C \times V) + 4CV = 3CV\)
- Compute the total capacitance when the capacitors are connected in parallel:
- The total capacitance: \(C_{\text{total}} = C + 2C = 3C\)
- Find the common potential:
- The common potential \( V_{\text{common}} \) is given by: \(V_{\text{common}} = \frac{Q_{\text{net}}}{C_{\text{total}}} = \frac{3CV}{3C} = V\)
Thus, the common potential when the capacitors are connected is \(V\). Therefore, the correct answer is option \( V \) .
This solution demonstrates the conservation of charge principle in capacitors connected in parallel with opposite polarities.