Question

Find the equivalent capacitance between A and B, where \( C = 16 \, \mu F \). 

• A. 48 \( \mu F \)
• B. 8 \( \mu F \)
• C. 32 \( \mu F \)
• D. 16 \( \mu F \)

Hint:

For complex capacitor networks, break the network into simpler series and parallel combinations, and use the formulas for equivalent capacitance to reduce the network step by step until you obtain the final equivalent capacitance.

Answer 1

The Correct Option is C

For capacitors in series, the reciprocal of the equivalent capacitance \( C_{\text{eq}} \) is the sum of the reciprocals of individual capacitances: \[\frac{1}{C_{\text{eq}}} = \frac{1}{C_1} + \frac{1}{C_2} + \dots\] For capacitors in parallel, the equivalent capacitance \( C_{\text{eq}} \) is the sum of individual capacitances: \[C_{\text{eq}} = C_1 + C_2 + \dots\] Given \( C = 16 \, \mu F \), and a configuration of series and parallel capacitors, the calculated equivalent capacitance between points A and B is \( 32 \, \mu F \).