Question:medium

Two capacitors \( C_1 \) and \( C_2 \) are connected in parallel to a battery. Charge-time graph is shown below for the two capacitors. The energy stored with them are \( U_1 \) and \( U_2 \), respectively. Which of the given statements is true? 

Show Hint

Capacitance affects charging time and the energy stored; a higher capacitance results in slower charging and more energy storage at the same voltage.
Updated On: Feb 2, 2026
  • \( C_1>C_2, U_1<U_2 \)
  • \( C_2>C_1, U_2>U_1 \)
  • \( C_2>C_1, U_2<U_1 \)
  • \( C_1>C_2, U_1>U_2 \)
Show Solution

The Correct Option is B

Solution and Explanation

Graph analysis reveals \( C_2 \) charges slower than \( C_1 \). This implies \( C_2 \) has a higher capacitance than \( C_1 \) (i.e., \( C_2>C_1 \)), as capacitance is inversely related to charging rate when voltage is constant. Since the energy stored \( U \) is directly proportional to capacitance \( C \) (from \( U = \frac{1}{2} C V^2 \)), the energy \( U_2 \) associated with \( C_2 \) will be greater than \( U_1 \).
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