\( 2.0 \, \text{A} \)
\( 1.0 \, \text{A} \)
Provided Information:
Ohm's Law formula: \[ I = \frac{V}{R} \] Variables: - \( I \) = current, - \( V \) = voltage, - \( R \) = resistance.
\[ I = \frac{10 \, \text{V}}{5 \, \Omega} = 2 \, \text{A} \]
The calculated current is \( \boxed{2.0 \, \text{A}} \).
Two charges \( +q \) and \( -q \) are placed at points \( A \) and \( B \) respectively which are at a distance \( 2L \) apart. \( C \) is the midpoint of \( AB \). The work done in moving a charge \( +Q \) along the semicircle CSD (\( W_1 \)) and along the line CBD (\( W_2 \)) are 
Find work done in bringing charge q = 3nC from infinity to point A as shown in the figure : 