Question

The vertex of the parabola $y=ax^2+bx+c$ is

• A. $(\frac{b}{2a}, \frac{b^2-4ac}{4a})$
• B. $(\frac{b}{2a}, \frac{4ac-b^2}{4a})$
• C. $(\frac{-b}{2a}, \frac{b^2-4ac}{4a})$
• D. $(\frac{-b}{2a}, \frac{4ac-b^2}{4a})$

Hint:

Vertex $x$-coordinate is always $-b/2a$ for any quadratic function.

Answer 1

The Correct Option is D