Find the distance between the points (0, 0) and (36, 15). Can you now find the distance between the two towns A and B ?

Question

Given that \( \cot \left( \frac{A+B}{2} \right) \cdot \tan \left( \frac{A-B}{2} \right) = \), and the equation \( \frac{x}{2} + \frac{y}{3} + \frac{2}{6} - 1 = 0 \), find the area of \( \Delta ABC = 2 \).

Answer 1

The distance between points (0, 0) and (36, 15) is calculated as follows:
\(=\sqrt{(36-0)^2+(15-0)^2}=\sqrt{36^2+15^2}\)
\(=\sqrt{1296+225}=\sqrt{1521}=39\)

The distance between towns A and B can be determined.
Town A is located at the origin (0, 0).
Consequently, town B is situated at point (36, 15) relative to town A.

Therefore, the distance between towns A and B is 39 km, as computed above.

Find the distance between the points (0, 0) and (36, 15). Can you now find the distance between the two towns A and B ?

Solution and Explanation

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