Question:medium

The velocity acquired by a charged particle of mass \(m\) and charge \(Q\) accelerated from rest by a potential \(V\) is

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Always equate electric potential energy with kinetic energy for acceleration problems.
Updated On: May 8, 2026
  • \(\frac{QV}{m}\)
  • \(\sqrt{\frac{m}{QV}}\)
  • \(\sqrt{mQV}\)
  • \(mQV\)
  • \(\sqrt{\frac{2QV}{m}}\)
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The Correct Option is

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