Question

Energy stored in a capacitor is given by the equation \[ E = \frac{1}{2} C V^2 \] where: - \( C \) is the capacitance, - \( V \) is the voltage, - \( E \) is the energy stored. Given the values of \( C \), \( V \), and \( E \), determine the energy stored.}

• A. \( E = \frac{1}{2} C V^2 \)
• B. \( E = C V \)
• C. \( E = C V^3 \)
• D. \( E = \frac{1}{2} C V \)

Hint:

Remember, the energy stored in a capacitor is proportional to the square of the voltage. Always use the formula \( E = \frac{1}{2} C V^2 \) to find the energy stored.

Answer 1

The Correct Option is A

The energy \( E \) stored in a capacitor is calculated using the formula: \[ E = \frac{1}{2} C V^2 \] Here, \( C \) represents the capacitance (in farads), \( V \) is the voltage (in volts), and \( E \) denotes the stored energy (in joules). By inputting the provided values for capacitance \( C \) and voltage \( V \) into this equation, the capacitor's stored energy can be determined.