Question

The total number of ‘Sigma’ and Pi bonds in 2 formylhex-4-enoic acid is ____.

Answer 1

Correct Answer: 22

Analysis of Bonds in 2-formylhex-4-enoic acid

Compound Structure: 

The molecular structure of 2-formylhex-4-enoic acid is presented as:

\(H–O–C(=O)–CH(CHO)–CH_2–CH=CH–CH_3\)

Carbon atoms are numbered \(C_1\) through \(C_6\).

Bond Analysis:

Single bonds are classified as \(\sigma\) (sigma) bonds. Double bonds consist of one \(\sigma\) and one \(\pi\) (pi) bond.

• Total sigma (\(\sigma\)) bonds: 19.
• Total pi (\(\pi\)) bonds: 3.

Detailed Explanation:

1. The molecule features both a carboxylic acid group (–COOH) and a formyl group (–CHO).

2. The C=O bonds within both functional groups contribute two \(\pi\) bonds.

3. The C=C double bond, located between carbons 4 and 5, contributes an additional \(\pi\) bond.

4. The sum of sigma and pi bonds is:

\[\sigma\text{-bonds} = 19, \quad \pi\text{-bonds} = 3\]

Final Answer:

\[\boxed{\sigma = 19, \quad \pi = 3}\]