Question:medium

Match List-I with the List-II
List-I
(Hybridization)		List-II
(Orientation in
Space)
(A) sp3(I) Trigonal
bipyramidal
(B) dsp2(II) Octahedral
(C) sp3d(III) Tetrahedral
(D) sp3d2(IV) Square planar
Choose the correct answer from the options given below:

Updated On: Apr 19, 2026
  • A-III, B-I, C-IV, D-II
  • A-II, B-I, C-IV, D-III
  • A-IV, B-III, C-I, D-II
  • A-III, B-IV, C-I, D-II
Show Solution

The Correct Option is D

Solution and Explanation

To correctly match hybridization states from List-I with their spatial orientations in List-II, understanding the geometry of each hybridization is necessary:

  1. sp3 hybridization, formed by mixing one s and three p orbitals, yields four equivalent orbitals. This results in a tetrahedral geometry with bond angles approximating 109.5°. Consequently, (A) sp3 corresponds to (III) Tetrahedral.
  2. dsp2 hybridization involves the mixing of one d, one s, and two p orbitals, leading to a square planar geometry. This geometry is typical in certain transition metal complexes. Thus, (B) dsp2 aligns with (IV) Square planar.
  3. sp3d hybridization arises from mixing one s, three p, and one d orbital, producing five hybrid orbitals. This configuration results in a trigonal bipyramidal geometry with two distinct bond angles. Therefore, (C) sp3d matches (I) Trigonal bipyramidal.
  4. sp3d2 hybridization is achieved by mixing one s, three p, and two d orbitals. This combination leads to an octahedral geometry, characterized by symmetry and 90° bond angles. Hence, (D) sp3d2 corresponds to (II) Octahedral.

The pairings between hybridization (List-I) and spatial orientation (List-II) are as follows:

List-I
(Hybridization)		List-II
(Orientation in Space)
(A) sp3(III) Tetrahedral
(B) dsp2(IV) Square planar
(C) sp3d(I) Trigonal bipyramidal
(D) sp3d2(II) Octahedral

The correct matches are: A-III, B-IV, C-I, D-II.

Was this answer helpful?
0

Top Questions on Hybridization

Questions Asked in JEE Main exam