To find the equivalent statement of the given expression, let's use the properties of logic statements involving logical conjunctions (∧), disjunctions (∨), and negations (~).
- The given statement is: \((p \land \neg q) \lor (\neg p \land q) \lor \neg q\).
- Let's consider distributing and simplify each part:
- The term \((p \land \neg q) \lor (\neg p \land q)\) appears to be like an XOR operation (exclusive OR), which means it is true when exactly one of the variables is true.
- In a simpler form, \((p \land \neg q) \lor (\neg p \land q)\) can cover all possibilities unless both are false or both are true (we simplify directly for logical equivalence purposes).
- Now, with the third part \(\neg q\), we have:
- If \(\neg q\) is true, the whole statement is true regardless of \(p\) as any \((False \lor True = True)\).
- Let's evaluate the combined expression.
- Note: Simplifying through logical inference: If \(\neg q\) is explicitly included, then whenever \(q\) is false, the entire expression satisfies as true.
- This covers cases when \(\neg q\) is true. But observe:
- For any term that starts with \((\neg p \land q)\), \(\neg q\) is always present.
- Revisiting the expression, since we have to check for variable impact:
- \((p \land \neg q) \lor (\neg p \land q) \lor \neg q = \neg p \lor \neg q\) as their presence will satisfy the conditions resulting in simplification into disjoint expressions \((\lor)\).
- Thus, the statement is logically equivalent to: \(\neg p \lor \neg q\).
Therefore, the correct answer is the option
(~ p) v (~q)
.