Question

The solution of $p = \tan(px - y)$ is (where $p = \frac{dy}{dx}$)

• A. $y = \tan^{-1}x + c$
• B. $y = \frac{c}{x} + \tan^{-1}c$
• C. $y = cx - \tan^{-1}c$
• D. $xy = \tan^{-1}c$

Hint:

Clairaut's form $y = px + f(p)$ always has the general solution $y = cx + f(c)$. Just swap $p$ for $c$!

Answer 1

The Correct Option is C