In a code, the \(r^{\text{th}}\) letter is shifted to the \((27-2r)^{\text{th}}\) letter for \(r = 1, 2, \ldots, 13\). The fourteenth letter is shifted to the \(26^{\text{th}}\) letter, and for \(r = 15, 16, \ldots, 26\), the \(r^{\text{th}}\) letter is shifted to the \((2r-28)^{\text{th}}\) letter. For decoding, the inverse process of the above is followed. Using this coding and decoding, answer the question: