Question:easy

The resistance of a semiconductor decreases when its temperature increases because:

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Contrast conductors and semiconductors:
In conductors (metals), $n$ is constant, and increasing temperature decreases $\tau$ (more collisions), so resistance increases (positive $\alpha$).
In semiconductors, increasing temperature increases $n$ exponentially, dominating over the change in $\tau$, so resistance decreases (negative $\alpha$).
  • the number of free charge carriers increases
  • electron mass decreases
  • atomic spacing increases
  • mobility becomes zero
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The Correct Option is A

Solution and Explanation

Step 1: Temperature effect.
Higher temperature excites more electrons to the conduction band, increasing free carrier density and reducing resistance.
Answer: number of free charge carriers increases
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