Question:easy

One mole of glucose molecules contains approximately:

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Remember that the value of Avogadro's number ($N_A = 6.022 \times 10^{23}$) is independent of the identity of the chemical species.
Whether you are dealing with one mole of glucose, one mole of water, or one mole of electrons, the count of those fundamental entities will always be $6.02 \times 10^{23}$.
  • 3.01 $\times$ 10$^{23}$ molecules
  • 6.02 $\times$ 10$^{23}$ molecules
  • 1.204 $\times$ 10$^{24}$ molecules
  • 9.03 $\times$ 10$^{23}$ molecules
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Recall Avogadro's number.
One mole of any substance contains $N_A = 6.02 \times 10^{23}$ particles.
Step 2: Apply directly.
1 mole of glucose = $6.02 \times 10^{23}$ molecules.
\[ \boxed{6.02 \times 10^{23} \text{ molecules}} \]
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