Question:medium

The ratio of the kinetic energies of the electrons in the third and fourth excited states of hydrogen atom is

Show Hint

Remember: $n$-th excited state means the principal quantum number is $(n+1)$. KE $\propto 1/n^2$, PE $\propto -1/n^2$, TE $\propto -1/n^2$.
Updated On: Mar 26, 2026
  • 4:3
  • 16:9
  • 25:16
  • 5:4
Show Solution

The Correct Option is C

Solution and Explanation

Was this answer helpful?
0

Top Questions on Modern Physics

Questions Asked in TS EAMCET exam