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The ratio of de Broglie wavelength of a deuteron with kinetic energy $E$ to that of an alpha particle with kinetic energy $2E$ is $n:1$. (Assume mass of proton $=$ mass of neutron.) Find the value of $n$.

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For de Broglie wavelength comparisons, focus on the product $mK$; constants cancel out immediately.

Updated On: Mar 24, 2026

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Correct Answer: 2

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The ratio of de Broglie wavelength of a deuteron with kinetic energy \(E\) to that of an alpha particle with kinetic energy \(2E\) is \(n:1\). (Assume mass of proton \(=\) mass of neutron.) Find the value of \(n\).

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Correct Answer: 2

Solution and Explanation

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