Question:medium

The ratio mass of oxygen and nitrogen of a particular gaseous mixture is $1 : 4$ The ratio of number of their molecule is

Updated On: Mar 31, 2026
  • $1 : 4$
  • $7 : 32$
  • $1 : 8$
  • $3 : 16$
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The Correct Option is B

Solution and Explanation

To determine the ratio of the number of molecules of oxygen and nitrogen in a mixture where the ratio of their masses is given as 1 : 4, we need to consider their respective molar masses and use the concept of number of moles.

  1. The molar mass of oxygen (O2) is approximately 32 \, \text{g/mol} and for nitrogen (N2), it is approximately 28 \, \text{g/mol}.
  2. The number of moles of a substance is given by the formula: \text{Number of moles} = \frac{\text{Mass}}{\text{Molar mass}}
  3. Let's assume the mass of oxygen is M and the mass of nitrogen is 4M since the mass ratio is 1 : 4.
  4. The number of moles of O2 is: \frac{M}{32}
  5. The number of moles of N2 is: \frac{4M}{28}
  6. The ratio of the number of molecules, which is proportional to the number of moles, will be: \frac{\left(\frac{M}{32}\right)}{\left(\frac{4M}{28}\right)}
  7. Simplifying the molecules ratio: \frac{M}{32} \times \frac{28}{4M} = \frac{28}{128} = \frac{7}{32}

Thus, the ratio of the number of molecules of oxygen to nitrogen is 7 : 32.

Therefore, the correct answer is 7 : 32. This is due to the inversely proportional relationship between the number of moles and molar mass when the masses are constant.

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