Question

When a 60 W electric heater is immersed in a gas for 100s in a constant volume container with adiabatic walls, the temperature of the gas rises by 5°C. The heat capacity of the given gas is_____J K^-1 (Nearest integer).

Answer 1

Correct Answer: 1200

The problem involves determining the heat capacity of a gas using the energy supplied and the temperature change. The formula to calculate the heat capacity (C) is based on the relationship: Q = C × ΔT, where Q is the heat supplied, and ΔT is the change in temperature.

Given:

• Power of heater (P) = 60 W
• Time (t) = 100 s
• Temperature change (ΔT) = 5°C

First, calculate the total heat supplied (Q) using the formula Q = P × t:

Q = 60 \, \text{W} \times 100 \, \text{s} = 6000 \, \text{J}

Substitute the values into the formula Q = C × ΔT to find C:

6000 = C \times 5

Solve for C:

C = \frac{6000}{5} = 1200 \, \text{J K}^{-1}

The calculated heat capacity is 1200 J K^-1.

This value falls within the given expected range of 1200 to 1200, confirming its correctness.