Question:medium

The radical axis of the circles \[ x^2+y^2+4x+6y+7=0 \] and \[ 4x^2+4y^2+8x+12y-24=0 \] is a tangent to the circle \[ x^2+y^2=13 \] at a point \((\alpha,\beta)\), then \(\alpha+\beta=\)

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The point of contact of a tangent to the circle \[ x^2+y^2=r^2 \] lies on the radius perpendicular to the tangent line. The radius vector is parallel to the normal vector of the tangent.
Updated On: Jul 18, 2026
  • \(0\)
  • \(-\dfrac52\)
  • \(1\)
  • \(-5\)
Show Solution

The Correct Option is D

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