Question

The pH and pOH of 0.1 M sulphuric acid are: (\(H_2SO_4\) dissociates completely to give 2 \(H^+\) ions per formula unit; \(pK_w = 14\))

• A. 0.1, 13.9
• B. 0.3, 13.7
• C. 0.7, 13.3
• D. 1.0, 13.0

Hint:

H2SO4 gives 2 H+ ions per molecule; use pH + pOH = 14.

Answer 1

The Correct Option is C

[H+]=2x10^-1M. pH=-(log2+log10^-1)=-(0.301-1)=0.699≈0.7. pOH=14-0.7=13.3.

\[\boxed{pH = 0.7,\ pOH = 13.3}\]