Question:medium
The path difference between the two waves $y_{1} = a_{1}\sin \left(\omega t - \frac{2\pi x}{\lambda}\right)$ and $y_{2} = a_{2}\cos \left(\omega t - \frac{2\pi x}{\lambda} +\phi\right)$ is
The path difference between the two waves $y_{1} = a_{1}\sin \left(\omega t - \frac{2\pi x}{\lambda}\right)$ and $y_{2} = a_{2}\cos \left(\omega t - \frac{2\pi x}{\lambda} +\phi\right)$ is
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Convert cosine to sine: $\cos\theta = \sin\left(\theta + \frac{\pi}{2}\right)$.
Updated On: Apr 8, 2026
- $\frac{\lambda}{2\pi}\phi$
- $\frac{\lambda}{2\pi}\left(\phi +\frac{\pi}{2}\right)$
- $\frac{2\pi}{\lambda}\left(\phi -\frac{\pi}{2}\right)$
- $\frac{2\pi}{\lambda}\phi$
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The Correct Option is B
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