Question

The output voltage in the following circuit is (Consider ideal diode case): 

• A. \( -5 \, \text{V} \)
• B. \( +5 \, \text{V} \)
• C. \( 10 \, \text{V} \)
• D. \( 0 \, \text{V} \)

Hint:

For ideal diodes, always remember that they conduct when forward biased and do not conduct when reverse biased. In this case, the conducting diode pulls the output voltage to 0V.

Answer 1

The Correct Option is D

To ascertain the output voltage in the provided circuit, we must analyze it under ideal diode conditions. An ideal diode exhibits perfect conductivity when forward-biased (zero voltage drop) and zero conductivity when reverse-biased (infinite resistance).

1. First, analyze diode \( D_1 \). Being forward-biased by \( +5 \, \text{V} \), it will conduct, permitting current flow with no voltage drop.
2. Subsequently, examine diode \( D_2 \). Its cathode is grounded, meaning the anode's potential is higher than ground during operation. Consequently, \( D_2 \) is reverse-biased.
3. Since \( D_1 \) conducts and \( D_2 \) does not, the output voltage \( V_{\text{out}} \) matches the cathode of the conducting diode \( D_1 \), resulting in \( +5 \, \text{V} \).

Finally, consider the resistor connected to the output. This resistor is also connected to \( +5 \, \text{V} \). With identical potentials at both connection points, no potential difference exists, establishing the output voltage \( V_{\text{out}} \) as \( 0 \, \text{V} \).

Therefore, the correct output voltage is:

\( 0 \, \text{V} \)