Question:medium

The objective of a microscope is immersed in a liquid of refractive index 1.5. If the semi-vertical angle of the cone of light rays of wavelength 600 nm from the object that fall on the objective is \(30^\circ\), then the minimum resolvable distance for this microscope is:

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For microscopes: \[ d=\frac{0.61\lambda}{NA}, \] where \[ NA=n\sin\theta. \]
Updated On: Jun 18, 2026
  • \(610\;nm\)
  • \(366\;nm\)
  • \(488\;nm\)
  • \(244\;nm\)
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The Correct Option is D

Solution and Explanation

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