Question:medium

The number of disintegrations per year of \(15.3\,\text{mg}\) sample of \({}^{60}_{27}\mathrm{Co}\) is \[ (\text{Mean life of }{}^{60}_{27}\mathrm{Co}\text{ is }7.65\text{ years and Avogadro's number }=6.024\times10^{23}\text{ mol}^{-1}) \]

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For radioactive decay, \[ \boxed{ A=\lambda N=\frac{N}{\tau}, } \] where \(\tau\) is the mean life.
Updated On: Jul 18, 2026
  • \(3624\times10^{16}\)
  • \(798\times10^{15}\)
  • \(2008\times10^{16}\)
  • \(1258\times10^{16}\)
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The Correct Option is C

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