




To determine the major product ‘P’ from the given reaction sequence, let's analyze each step:
The reaction of the given alcohol with thionyl chloride (SOCl2) converts the hydroxyl group (-OH) into a chloro group (-Cl) via nucleophilic substitution. This forms an acyl chloride.
Amines react with acyl chlorides to give amides. Thus, the product from Step 1 reacts with R-NH2, forming an amide linkage.
Lithium aluminium hydride (LiAlH4) reduces amides to amines. So, the amide from Step 2 is reduced to the corresponding amine.
The final treatment with acidic water (H3O+) completes the transformation, stabilizing the amine product and ensuring any intermediates are fully reacted.
The final major product ‘P’ from these steps is an amine formed through the reduction of the amide intermediate.
Upon reviewing the options, the structure matching the amine formed is shown as the correct answer.
Calculate the potential for half-cell containing 0.01 M K\(_2\)Cr\(_2\)O\(_7\)(aq), 0.01 M Cr\(^{3+}\)(aq), and 1.0 x 10\(^{-4}\) M H\(^+\)(aq).
