




The given reaction involves the reduction of a carboxylic acid and an ester group using lithium aluminum hydride (LiAlH4), followed by acid hydrolysis. Let's break down the problem step by step:
Therefore, the major product of the reaction is the compound with both the carboxylic acid and ester groups reduced to primary alcohols.
Calculate the potential for half-cell containing 0.01 M K\(_2\)Cr\(_2\)O\(_7\)(aq), 0.01 M Cr\(^{3+}\)(aq), and 1.0 x 10\(^{-4}\) M H\(^+\)(aq).
