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the function x y tan 1 y ...
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The function \[ x+y=\tan^{-1}y \] is the solution of which of the following differential equations?
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While differentiating implicitly, remember that the derivative of \(y\) with respect to \(x\) is always written as \(y'\) or \(\dfrac{dy}{dx}\).
COMEDK UGET - 2026
COMEDK UGET
Updated On:
May 16, 2026
\(y^2y'+y^2+1=0\)
\(y^2y''-2y'=0\)
\(y^2y'-y^2+1=0\)
\(y^2-2y'+1=0\)
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The Correct Option is
A
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