Question

The solution of \( (x+\log y)dy+ydx=0 \) when \( y(0)=1 \) is

• A. \( y(x-1+\log y)+1=0 \)
• B. \( xy+y\log y+1=0 \)
• C. \( xy-y\log y-y=1 \)
• D. \( y(x+1+\log y)-1=0 \)

Hint:

When a differential equation contains \( dx \) and \( dy \), try to identify whether it becomes a linear differential equation by treating \( x \) as a function of \( y \).

Answer 1

The Correct Option is A