The following table shows the total number of people who were stuck in traffic jam while going to their office on working days of a week due to construction of a flyover. Table also shows the ratio of male to female among them. If 30% males on Tuesday and 60% males on Wednesday reached their office on regular time of the office, then how many males got late on Tuesday and Wednesday taken together?
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Multi-step data interpretation problems require careful calculation at each stage. A small error in an early step (like calculating the number of males) will lead to an incorrect final answer. Always double-check your intermediate results.
Step 1: Calculate Tuesday's late male count.
- Tuesday total = 4800.
- Male:Female ratio = 1:5; Total parts = 6.
- Tuesday males = \( 4800 \times \frac{1}{6} = 800 \).
Step 2: Calculate Tuesday's late males.
- 30% of males arrived on time, so \(100% - 30% = 70%\) were late.
- Tuesday late males = \( 800 \times 0.70 = 560 \).
Step 3: Calculate Wednesday's male count.
- Wednesday total = 5000.
- Male:Female ratio = 3:7; Total parts = 10.
- Wednesday males = \( 5000 \times \frac{3}{10} = 1500 \).
Step 4: Calculate Wednesday's late males.
- 60% of males were on time, implying \(100% - 60% = 40%\) were late.
- Wednesday late males = \( 1500 \times 0.40 = 600 \). Checking: 1500 * 0.4 = 600.
- Recalculating. Wednesday M:F = 3:7. Males = 1500. 60% on time \textrightarrow 40% late. 1500 * 0.4 = 600. Correct.
Reviewing Q66.
Tuesday: Total 4800, M:F=1:5. Males=800. 30% on time \textrightarrow 70% late. Late = 800 * 0.7 = 560.
Wednesday: Total 5000, M:F=3:7. Males=1500. 60% on time \textrightarrow 40% late. Late = 1500 * 0.4 = 600.
Total late males = 560 + 600 = 1160.
Result doesn't match options. Re-examining the table: Tuesday M:F is 1:5. Wednesday M:F is 3:7. Numbers are correct.
Could the percentages apply to the total? No, it states "30% males".
Recalculating: 800 * 0.7 = 560. 1500 * 0.4 = 600. Sum = 1160.
Possible table error.
Monday: 6300, 3:4
Tuesday: 4800, 1:5
Wednesday: 5000, 3:7
Thursday: 2500, 2:3
Friday: 5400, 4:5
Values and calculations are correct. Reviewing the question: "how many males got late". Steps are correct.
Considering the question may intend "females".
Tuesday Females = 4000. Late = 4000 * 0.7 = 2800.
Wednesday Females = 3500. Late = 3500 * 0.4 = 1400. Sum = 4200. Incorrect.
Considering the percentage refers to those who were late.
Late males Tue = 800 * 0.3 = 240.
Late males Wed = 1500 * 0.6 = 900.
Total = 240 + 900 = 1140. Still doesn't match.
Likely data or option error. Working backwards from option A, 1290.
If Total Late = 1290, and Wed Late = 600, Tue Late must be 1290-600=690.
For Tue Late of 690, if 70% were late, Total Males = 690/0.7 = 985.7. Non-integer.
If 30% were late, Total Males = 690/0.3 = 2300. Not 800.
