To determine which lanthanide ions have half-filled and completely filled f orbitals, we must consider the electronic configurations of the elements and their ions.
- The lanthanides have the general electron configuration \([Xe] 4f^n 6s^2\).
- Half-filled Orbitals: A half-filled f subshell has 7 electrons (since the f subshell can hold up to 14 electrons).
- Completely filled Orbitals: A completely filled f subshell has 14 electrons.
Let's analyze the provided atomic numbers:
- Europium (\(Eu\)): Atomic number 63, configuration is \([Xe] 4f^7 6s^2\).
\([Eu^{2+}]:\) Removing 2 electrons gives \(4f^7\), a half-filled configuration.\) - Thulium (\(Tm\)): Atomic number 69, configuration is \([Xe] 4f^{13} 6s^2\).
\([Tm^{2+}]:\) Removing 2 electrons gives \(4f^{13}\), not full nor half.\) - Ytterbium (\(Yb\)): Atomic number 70, configuration is \([Xe] 4f^{14} 6s^2\).
\([Yb^{2+}]:\) Removing 2 electrons gives \(4f^{14}\), a completely filled configuration.\) - Terbium (\(Tb\)): Atomic number 65, configuration is \([Xe] 4f^9 6s^2\).
\([Tb^{4+}]:\) Removing 4 electrons results in \(4f^7\), a half-filled configuration.\)
Let's evaluate the answer choices:
- \(Eu^{2+}\) and \(Tm^{2+}\): Eu has a half-filled, but Tm does not have either half or full-filled.
- \(Sm^{2+}\) and \(Tm^{3+}\): Sm also doesn't result in a half or fully filled f-orbital, and neither does Tm in its 3+ state.
- \(Tb^{4+}\) and \(Yb^{2+}\): Tb results in a half-filled, and Yb results in a completely filled configuration, fulfilling the requirement.
- \(Dy^{3+}\) and \(Yb^{3+}\): Dy does not have half or fully filled f-orbital either.
Thus, the correct answer is \(Tb^{4+}\) and \(Yb^{2+}\) because they satisfy the conditions of half-filled and completely filled f-orbitals, respectively.