Question:medium

Which trend is correct regarding ionic radius in the 4f-series (lanthanides)?

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Remember "lanthanide contraction"—as you move from La\(^{3+}\) to Lu\(^{3+}\), the size of ions decreases due to ineffective shielding by 4f electrons.
Updated On: Jan 13, 2026
  • Radius increases from La\(^{3+}\) to Lu\(^{3+}\)
  • Radius remains same
  • Radius decreases across the series
  • No regular trend observed
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The Correct Option is C

Solution and Explanation


As electrons are added to the 4f orbitals across the lanthanide series (from La\(^{3+}\) to Lu\(^{3+}\)), their poor shielding effect results in an increased effective nuclear charge. This enhanced attraction draws electrons nearer to the nucleus, causing a progressive reduction in ionic radii, a phenomenon termed lanthanide contraction.
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