Question:medium

The equation of a wave on a string of linear mass density \(0.02 \text{kg m}^{-1}\) is \(Y = 0.01sin[2π(\frac{t}{0.02}-\frac{x}{0.50})]\) m. The tension in the string is

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Read omega and k from the wave equation, find the speed, then use v = root of T over mu.
Updated On: Oct 1, 2026
  • \(12.50\) N
  • \(6.25\) N
  • \(25\) N
  • \(50\) N
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Approach
Use the ratio of angular frequency to wave number.

Step 2: Values
$\omega=\dfrac{2\pi}{0.02}=100\pi$ rad/s and $k=\dfrac{2\pi}{0.50}=4\pi$ rad/m. So $v=\omega/k=25$ m/s.

Step 3: Tension
$T=\mu v^2=0.02\times25^2=12.5$ N. Option (A).

Final Answer:
The wave speed is 25 m/s, so the tension is 0.02 times 625 = 12.5 N, option (A). \[ \boxed{12.50\ \text{N}} \]
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