The energy stored in a capacitor of capacitance C having a charge Q under a potential V is
Show Hint
- \(\frac{1}{2}Q^2V\)
- \(\frac{1}{2}C^2V\)
- \(\frac{1}{2}\frac{Q^2}{V}\)
- \(\frac{1}{2}QV\)
- \(\frac{1}{2}CV\)
The Correct Option is D
Solution and Explanation
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