Question

The current amplification factor of a transistor in common emitter configuration is 80. If the emitter current is 2.43 mA, then the base current is

• A. 15 $\mu$A
• B. 1.5 $\mu$A
• C. 3 $\mu$A
• D. 30 $\mu$A

Hint:

For a transistor, always remember the core current relationship ($I_E=I_C+I_B$) and the current gain for the common emitter configuration ($\beta=I_C/I_B$). This allows you to quickly derive the relation $I_E = (\beta+1)I_B$, which is the key to solving this type of problem.

Answer 1

The Correct Option is D