Question:medium

The correct increasing order of spin-only magnetic moment values of the complex ions:

[MnBr4]2− (A),
[Cu(H2O)6]2+ (B),
[Ni(CN)4]2− (C), and
[Ni(H2O)6]2+ (D)

is:

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For magnetic moment problems: 1. Determine oxidation state and \(d\)-electron count. 2. Identify ligand strength (weak field → high spin, strong field → low spin). 3. Count unpaired electrons and apply \(\mu = \sqrt{n(n+2)}\).
Updated On: Mar 25, 2026
  • A = B<C<D
  • B<D<C
  • C<B<A
  • C<B<D<A
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The Correct Option is D

Solution and Explanation

To determine the correct increasing order of spin-only magnetic moment values of the given complex ions, we need to understand the concept of magnetic moments in coordination chemistry. The spin-only magnetic moment for a complex is given by the formula:

\[\mu = \sqrt{n(n+2)} \, \text{Bohr Magneton (B.M.)}\]

where n is the number of unpaired electrons in the complex. Let us analyze each complex ion:

  1. [MnBr4]2− (A): Mn in this complex is in +2 oxidation state. Electronic configuration of Mn2+ is [Ar] 3d5, which means there are 5 unpaired electrons. Therefore, the spin-only magnetic moment is \[\mu = \sqrt{5(5+2)} = \sqrt{35} \approx 5.92 \, \text{B.M.}\].
  2. [Cu(H2O)6]2+ (B): Cu in this complex is in +2 oxidation state. Electronic configuration of Cu2+ is [Ar] 3d9, which means there is 1 unpaired electron. Therefore, the spin-only magnetic moment is \[\mu = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73 \, \text{B.M.}\].
  3. [Ni(CN)4]2− (C): Ni in this complex is in +2 oxidation state, and CN is a strong field ligand causing pairing of electrons. Hence, the electronic configuration is [Ar] 3d10, and there are 0 unpaired electrons. Therefore, the spin-only magnetic moment is \[\mu = \sqrt{0(0+2)} = 0 \, \text{B.M.}\].
  4. [Ni(H2O)6]2+ (D): Ni in this complex is in +2 oxidation state. The electronic configuration of Ni2+ is [Ar] 3d8 with 2 unpaired electrons. Therefore, the spin-only magnetic moment is \[\mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.83 \, \text{B.M.}\].

Thus, the increasing order of spin-only magnetic moments is:

C < B < D < A

This matches the given correct answer.

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