The compound that is white in color is

Question

Statement-I : Consider the following pairs of ions $(\text{Sc}^{3+}, \text{Ti}^{3+}), (\text{Ti}^{4+}, \text{Ni}^{2+}), (\text{Cu}^{2+}, \text{Zn}^{2+})$ and $(\text{Cr}^{3+}, \text{Mn}^{3+})$. Out of these pairs three pairs consist of ions that are both coloured :
Statement-II : Among the lanthanide ions $\text{Eu}^{2+}$, $\text{Gd}^{3+}$, $\text{Ce}^{4+}$ and $\text{Tb}^{4+}$, the ion $\text{Tb}^{4+}$ is the strongest reducing agent.
Choose the correct option.

Answer 1

To identify the white compound, the properties of each candidate are assessed:

Ammonium sulphide: Typically yellow due to sulfur content, characteristic of sulfides. Not white.
Lead sulphate: ($ \text{PbSO}_4 $) Is a known white, water-insoluble solid. This compound is a likely candidate for being white.
Lead iodide: ($ \text{PbI}_2 $) Is a bright yellow solid. Its color excludes it from being the white compound.
Ammonium arsinomolybdate: Less common, often forms variable-colored complexes. Without specific data, its color cannot be presumed white.

Based on this evaluation, lead sulphate is the compound definitively identified as white among the given choices.

The correct answer is lead sulphate.

The compound that is white in color is

The Correct Option is B

Solution and Explanation

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