The capacitance of a capacitor with charge q and a potential difference V depends on :
- both q and V
- the geometry of the capacitor
- q only
- V only
The Correct Option is B
Solution and Explanation
Capacitance (C) is calculated as the quotient of charge (q) by potential difference (V):
$C = \frac{q}{V}$
Nevertheless, capacitance is fundamentally dictated by the capacitor's physical construction, specifically its plate area, the spacing between plates, and the dielectric material. While charge (q) and potential difference (V) are proportional to capacitance, they do not define it. A capacitor, based on its inherent geometry, possesses a constant capacitance value.
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