Question:medium
Sum of \( \frac{1^3}{1} + \frac{1^3 + 2^3}{1 + 3} + \frac{1^3 + 2^3 + 3^3}{1 + 3 + 5} + \dots \) up to 8 terms is:
Sum of \( \frac{1^3}{1} + \frac{1^3 + 2^3}{1 + 3} + \frac{1^3 + 2^3 + 3^3}{1 + 3 + 5} + \dots \) up to 8 terms is:
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The sum of the first \( n \) odd numbers is always \( n^2 \). This often simplifies series problems where the denominator looks complex.
Updated On: Apr 3, 2026
- 71
- 70
- 73
- 72
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The Correct Option is D
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